Even number list while using if statement with a % function

Python Help
1

I’m stuck with this prompt and don’t know where to start since they threw remainder function in here:

Write a function printing every even numbers in the given range, one number per line.

Your function have to be named print_even_numbers and accept two parameters named start and stop.

Like Python’s range, you’ll have to start searching for even numbers by including start but excluding stop, remember:

for i in range(0, 10):
    print(i)

gives:

0
1
2
3
4
5
6
7
8
9

so what I want print_even_numbers(0, 10) to give:

0
2
4
6
8

Hints

You can use the remainder of a value divided 2 to tell if it’s odd or even. And in Python to get this remainder use the % operator, see:

>>> 2 % 2
0
>>> 3 % 2
1
>>> 4 % 2
0
>>> 5 % 2
1
>>> 6 % 2
0

The remainder is 1 if the value is odd and 0 if the value is even.

You’ll have to use an [if statement and a [print]

2

My input:
<def print_even_numbers(start, stop):
for num in (start,stop):
if num % 2 == 0:
print(print_even_numbers)>
Error I get:
Looks like your function is ignoring the given start and stop arguments.

For example, when I call print_even_numbers(0, 10) I get:

<function print_even_numbers at 0x7f2cf3129550>
<function print_even_numbers at 0x7f2cf3129550>

And, when I call print_even_numbers(10, 20) I get:

<function print_even_numbers at 0x7f2cf3129550>
<function print_even_numbers at 0x7f2cf3129550>
3

I was overthinking and forgot range
correct answer:
def print_even_numbers(start, stop):
for num in range(start,stop):
if num % 2 == 0:
print(num)

4

I was overthinking and forgot range
correct answer:
def print_even_numbers(start, stop):
for num in range(start,stop):
if num % 2 == 0:
print(num)

Please remember to surround code with “code fences”, a line of triple
backticks. This preserves formatting and indentation, which are very
important. Example:

 ```
 paste your
 code here
 ```

I just wanted to point out the other issue in your previous attempt: it
was not calling the function. This statement:

 print(print_even_numbers)

does not call (“run”) the function. It just prints a reference to the
function itself, hence the odd looking output.

Functions are objects and can be bound to names like any other Python
object. For example:

 >>> x = 1
 >>>
 >>> def y():
 ...     print("y function!")
 ...
 >>> print(x)
 1
 >>> print(y)
 <function y at 0x107982280>
 >>>
 >>> y()
 y function!

Only when you call the y function by saying y() does it actually
operate.

Cheers,
Cameron Simpson cs@cskk.id.au