# Display the List
**URL:** https://discuss.python.org/t/display-the-list/13334
**Category:** Python Help
**Tags:** help
**Created:** [January 25, 2022, 12:55pm UTC](https://discuss.python.org/t/display-the-list/13334 "2022-01-25T12:55:53Z")
**Posts on this page:** 2
**Page:** 1
### Author:  [@vhegde](https://discuss.python.org/u/vhegde)
#### Post date: [January 25, 2022, 12:55pm UTC](https://discuss.python.org/t/display-the-list/13334/1 "2022-01-25T12:55:53Z")
Hi,
I have a List based on the user input.[‘r’, ‘r’, ‘r’, ‘r’, ‘s’, ‘S’, ‘P’, ‘P’, ‘s’, ‘s’, ‘p’]
I want to print this list as[“Rock”,Rock",Rock",Rock",Scissors",Scissors", “Paper”, “Paper”,“Scissors”,Scissors",“Paper”] depending on the user input.
The user input may change. I want to display whatever user enters in terms of [“Rock”, “Paper”, “Scissors”].
Could you please help me with this?
---
### Author:  [@cameron](https://discuss.python.org/u/cameron)
#### Post date: [January 25, 2022, 9:52pm UTC](https://discuss.python.org/t/display-the-list/13334/2 "2022-01-25T21:52:24Z")
We can and will help, but this looks very much like a homework exercise.
We ask that you supply your attempt at this and ask questions, as the
point is to learn by solving the problem yourself.
You have a list of inputs. You want them associated with words like
“Rock” etc. The normal way to do this in Python is with a mapping,
usually a dict, which is an object with keys (such as “r”) and
associated values (such as “Rock”). Example:
```
wordmap = {
'a': 'apple',
'b': 'banana',
}
```
When you access a mapping via a key your get a value:
```
f = 'a'
fruit = wordmap[f]
print(f, fruit)
```
should print:
```
a apple
```
Try writing some code on that basis and see how it goes. Return with the
code and questions. If you have error tracebacks, include them
_completely_. Please don’t use screenshots, instead copy/paste the code
(and/or traceback) into the message as text between triple backticks:
````
```
your pasted stuff here
```
````
Cheers,
Cameron Simpson [cs@cskk.id.au](mailto:cs@cskk.id.au)