Error in Python compiler?

To my surprise I still get the error via the command ‘python’ as well as via Python IDLE as follows:

mdx = ‘inp’
print(’-111-’ + mdx)
if mdx != ‘ínp’:
__print(’-222-’ + mdx) # where _ stands for space
print(’-333-’ + mdx)

It gives:
-111-inp
-222-inp
-333-inp

mdx = ‘nrm’
print(’-111-’ + mdx)
if mdx != ‘nrm’:
__print(’-222-’ + mdx)
print(’-333-’ + mdx)

It gives:
-111-inp
-333-inp

What should I have done wrong? Or is there a bug in the python compiler? I am using the Python 3.9.6.

It’s very hard to tell what you’re expecting to be different than
what you’re seeing, and why. All I can guess without more context is
that your font doesn’t distinguish “ínp” from “inp” and you’re
assuming they’re the same string when they aren’t.

You are not testing what you think you are. Let us do the following:

mdx = 'inp'
print('-111-' + mdx)
for a in 'ínp':
    print(ord(a), ":", a)
if mdx != 'ínp':
  print('-222-' + mdx) # where _ stands for space
print('-333-' + mdx)

…where I copied the ‘inp’ in the line for a in 'ínp': from your test. This results in the output:

-111-inp
237 : í
110 : n
112 : p
-222-inp
-333-inp

chr(237) is not an i but an i with a grave accent.

Hi Pejamide,

As a beginner to Python, any time you think that there might be an error

in the Python compiler, there isn’t.

In your first example, you are comparing the string ‘inp’ with the

string ‘ínp’:

  • String ‘inp’:

    • first letter is LATIN SMALL LETTER I

    • or chr(105)

  • String ‘ínp’

    • first letter is ‘LATIN SMALL LETTER I WITH ACUTE’

    • or chr(237)

So the two strings are unequal, and the output is correct.

In your second example, you are comparing the string ‘nrm’ with the

string ‘nrm’, both strings are the same, and so again the output is

correct.