Hello,
I would like to manage to solve this kind of equations :
eq1 = sym.Eq(asym.exp(-b90),33)
eq2 = sym.Eq(asym.exp(-b92),66)
I first tried with one equation this and it worked:
import sympy as sym
from sympy import solveset, S
from sympy.abc import x
from sympy import Symbol
a = symbols('a')
eq=sym.Eq(sym.exp(a*90),33)
solveset(eq,a,domain=S.Reals)
Then I tried this but it didn’t work :
a,b = symbols('a,b')
eq1 = sym.Eq(a*sym.exp(-b*90),33)
eq2 = sym.Eq(a*sym.exp(-b*92),66)
result=sym.solveset([eq1,eq2],(a,b),domain=S.Reals)
I get this error :
import sympy as sym
from sympy import solveset, S
from sympy.abc import x
from sympy import Symbol
a,b = symbols('a,b')
eq1 = sym.Eq(a*sym.exp(-b*90),33)
eq2 = sym.Eq(a*sym.exp(-b*92),66)
result=sym.solveset([eq1,eq2],(a,b),domain=S.Reals)
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
Input In [59], in <cell line: 9>()
7 eq1 = sym.Eq(a*sym.exp(-b*90),33)
8 eq2 = sym.Eq(a*sym.exp(-b*92),66)
----> 9 result=sym.solveset([eq1,eq2],(a,b),domain=S.Reals)
File C:\ProgramData\Anaconda\lib\site-packages\sympy\solvers\solveset.py:2178, in solveset(f, symbol, domain)
2175 return S.EmptySet
2177 if not isinstance(f, (Expr, Relational, Number)):
-> 2178 raise ValueError("%s is not a valid SymPy expression" % f)
2180 if not isinstance(symbol, (Expr, Relational)) and symbol is not None:
2181 raise ValueError("%s is not a valid SymPy symbol" % (symbol,))
ValueError: [Eq(a*exp(-90*b), 33), Eq(a*exp(-92*b), 66)] is not a valid SymPy expression
Does anyone have an idea of how I could proceed? Maybe solveset is not the adapted function?
Thanks for reading