16 Channel Multiplexer

Semi-new to coding.
Equipment: ESP8266 board, CD74HC4067 16-Channel Multiplexer

Code Platform: micropython using Thonny on RPi transmitting over USB cable.

Project Goal: 16 individual photo-resistors to trigger individual LEDs or Relays.

Code:
Opening Line…

from machine import Pin, ADC
from time import sleep_ms

s0 = Pin(16, Pin.OUT) # assigns s0 on multiplexer to D0 pin on ESP8266
s1 = Pin(5, Pin.OUT)  # D1
s2 = Pin(4, Pin.OUT)  # D2
s3 = Pin(2, Pin.OUT)  # D4
SIG_pin = ADC(0)  # assigns SIG on multiplexer to A0 pin on ESP8266

to test the code, I ran the super simple…

val = Sig_pin.read()
print(val)

and I get a value which reflects an output… i’m not sure from which of the (16) channels. If i comment 3 out of 4 of the s# pins, I get a change in value as expected… but again, I’m not sure which channel from the active pin.

I have thought about it and I can create a binary directory to use for the channels.

mux = [{0b0000},{0b0001},{0b0010},{0b0011}],[{0b0100},{0b0101},{0b0110},{0b0111}],[{0b1000},{0b1001},{0b1010},{0b1011}],[{0b1100},{0b1101},{0b1110},{0b1111}]

In arduino, i could use digitalWrite(pin,channel) to call for a specific channel, but how can I do this in python?
and then how can I get the Sig_pin to read that specific pin & channel?

Solved the problem. I was overthinking the process way too much.

ch1 = (s0.value(0), s1.value(0), s2.value(0), s3.value(0))
val = Sig_pin.read()
print(val)

Setting each of the s# pins to a high low state gives me my binary combination.

Cool. Sometimes it helps (I find, least ways) to explain an issue to others, in order to come up with an answer myself, not always, but often times.