Can Protocol methods have actual implementation?

Python Help
1

I’m using typing.Protocols a lot (actually, typing_extensions.Protocol because I try to take advantage of additional functionalities added in Python >= 3.11) and I’m a bit confused about the fact that Protocols can have implementation and child classes directly inheriting from said protocols use said implementations when no method is defined.

i.e.

from typing_extensions import Protocol, runtime_checkable

@runtime_checkable
class MyProtocol(Protocol):
    def my_method(self) -> None:
        ...

@runtime_checkable
class InheritProto(MyProtocol, Protocol):
    def my_method(self) -> None:
        print("InheritProto.my_method called")

class ExampleClass(InheritProto):
    ...

obj = ExampleClass()
obj.my_method()

In this case, when calling my_method, I originally suspected that the interpreter would give me some error of some sort saying that a Protocol shouldn’t have an implementation or something, but apparently it works.

Of course the benefit of Protocols is that can classes also be structurally identical to a protocol and being able to recognized as such when using @runtime_checkable (with all the warnings about the fact that the check may be expensive for protocols with a lot of methods). So… is there any point about using ABC at all at this point? What’s the catch? I’m definetely missing something here.

EDIT: while writing it got me thinking that maybe I’m losing the ability of using metaclasses in some capacity, but I have very little experience with those and rarely ever used them.