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I want to convert all values in the columns of my dataset into binary representation of 20 bits, and create a list of those values.

ex. 0.1234 as 00000001001000110100 1.2002 as 00010010000000000010 and so on

I tried doing it for a number, but for whole dataset, I’m unable to do so.

```
#let one of the values to be converted is 'v1'
v1 = 12.569
whole, dec = str(v1).split(".")
dig1 = [int(d) for d in str(whole)]
dig2=[int(e) for e in str(dec)]
res = dig1+dig2
newl=[]
for i in res:
newl.append(bin(int(i))[2:].zfill(4))
newl
for m in newl:
print(m, end="")
```

It results in: 00010010010101101001

But for a whole column (or multiple columns) of my dataset, I’m unable to do so

```
df1_ = [0.4, 0.3, 0.2, 0.5, 0.6]
newl=[]
enc1=[]
for vals in df1_:
whole, dec = str(vals).split(".")
#whole = int(whole)
dig = [int(d) for d in str(whole)]
dig2=[int(e) for e in str(dec)]
res = dig+dig2
for i in res:
#l = 4
newl.append(bin(int(i))[2:].zfill(4))
s = [str(y) for y in newl]
res1 = int("".join(s))
enc1.append(res1)
enc1
```

The output is as follows: [100, 10000000011, 1000000001100000010, 100000000110000001000000101, 10000000011000000100000010100000110]

But I want output as: [00000100,00000011,00000010,00000101,00000110]