Function call Return Challenge

Users
#1

Below is the code I have written.
Expecting “Clean.txt” in return but receiving “Clean” only.
Can someone help?

def openclose(filename):
filename=filename+".txt"
print(“Filename =”,filename)
filenameptr=open(filename,“w”);
if filename:
print(“File Opened Successfully”,filename)
filenameptr.close()
return filename

filenamz=“Clean”
print(“Call OpenClose(filename)”)
openclose(filenamz)
print("Return File Name is ",filenamz)

#2

You are returning “Clean.txt”, but you never change filenamz. Because you do not assign the returned value to any name, it is discarded and filenamz remains the same.

#3

Thanks for guiding Sir.
I was thinking that i am returning filename which is Clean.txt.
And my passed/returning variable is filenamz. So was thinking that no need to re-assign.
Will do as you guided. Thanks.

It’s been long time since programming is left :), re-entering into.

#4

Just wondering, when i m returning into “filenamz” and directly printing the same, why it’s not storing “Clean.txt”…

#5

Because you are telling Python to discard it.

>>> filenamz = "Clean"
>>> def ret_file(filename):
...     return filename + ".txt"
... 
>>> ret_file(filenamz)
'Clean.txt'
>>> filenamz
'Clean'

The above is what you are doing. You see it is returning “Clean.txt”, but it is discarded.

>>> filenamz = ret_file(filenamz)
>>> filenamz
'Clean.txt'

This is what you should do to get the expected outcome.

To get more feeling for names and what these mean in Python, see this video.