How to separate code

i want it so its doesnt run a script with the rest of the scripts

We’ll need a lot more information to understand what you’re asking for. What is happening right now? What do you mean “run a script” and “the rest of the scripts”?

To me, running a script means typing python on the command line. No other scripts are getting run when I do this–unless is launching new scripts as part of its code. So I’m not sure what you are trying to do.


if you mean that you only want to run a partial segment of your script, this is possible with PyCharm (I am sure you may do it also with other IDEs, however).

Suppose you have the following sequence of print statements in your script for simplicity:

print('Today is Thursday.')

print('Math is the language of physics.')
print('We are on the Python platform.')

If you highlight the bottom two lines, right-click, then select the following in the pop-up menu:

Execute selection in Python Console

It will only run the bottom two lines.

If you mean that you want to run only test code for a particular module without affecting other modules in a series of associated modules in your program, you can use the following line of code at the bottom of the module:

if __name__ == '__main__':

    " Provide module test code here

i need so if a input is inputted it doesnt run a specific script
basically i made it so that the correct input lets you input your username
but a incorrect input says: “license key invalid run app again” and then keyboard interrupts
but when input the correct input it does the same if you incorrectly input
so basically i want it so if you input a correct input then it doesnt run the incorrect input script along with it

I think we are using different definitions for these words–I think of a “script” as being a python file, and the only input possible is to run it on the command line. It sounds like you’re talking about behavior inside the script. So what you’re saying doesn’t make sense to me.

Can you show some examples of your code, and how you interact with it, and what is going wrong? Make sure to format the code according to the pinned post for this category.

ok, change script to code i guess

Have you considered dividing your script up into functions? Then at specific points you can run only the code you want to have run, and skip the stuff you don’t want to run.
something like

if validate_username():

def validate_username():
    ok = False
    input('enter username')
    if ... :      # put validation code here
        ok = true
    return ok

def do_something():
     .... # put processing stuff here

my example is

licensekey = input("Enter License Key")
licensekey = 824
if licensekey>=824:
    print("license key invalid rerun and try again")

for some reason it also runs the incorrect input code

The KeyboardInterrupt is simply the name of an exception. It doesn’t raise a keyboard interrupt on its own.

To raise a KeyboardInterrupt you need raise KeyboardInterrupt, but it’s a strange thing to do. Using quit() is better.

1 Like

wasnt related to my question but its literally the same if i did keyboardinterrupt

>>> licensekey = input("Enter License Key")
Enter License Key12345
>>> print(licensekey)
>>> licensekey = 824
>>> print(licensekey)

Whatever the user enters is immediately overwritten. Either remove the licensekey = 824 line, or use a different name.

licensekey = input("Enter License Key: ")
limit = 824
if licensekey >= limit:
    print("license key invalid rerun and try again")

Note that you can’t directly compare the result of input (which is a string) against an integer

Do you mean: “When I try running this code, I see the "license key invalid rerun and try again" output, but I think I should not see that”?

Well, of course you see that.

The first thing that happens is that you ask for a license key.

The second thing that happens is that you ignore what was input, by replacing it with the number 824.

The third thing that happens is that you make the comparison. As it happens, 824 is equal to 824, therefore it is “greater-than-or-equal-to” (>=) 824. So the code inside the if block does run.

I will make a guess that you added the licensekey = 824 because you were getting errors before. The reason for those errors is because you cannot compare a string to an integer. When you use input, you get a string back, even if it only contains numeric digits. No automatic conversion happens. Integers are a fundamentally different kind of thing.

so i cant make it so it doesnt run it when i input a correct input

No, it means that the code as written does not currently do that.

It is still not clear to me what you want here, but your code seems to
be doing its test for “correct” incorrectly.

First: you need to convert the result from input(), which is a
string, to an integer. Your test compares against an integer, and
comparing a string to an integer is always false - the test will just

The usual way we do this in learning programmes like yours is:

 value = int(input(..................))

This takes the result of input(......), which is a string (because it
is something the user has typed), and passes that to the function
int(), which will accept a valid integer string, and return to
corresponding integer. And then stores the result of calling int() in
the variable.

Now that your input value is an integer, then you can test it for

The second issue seems to be that you, having read a value using
input(), then ignore it and assign another value. That means that your
correctness test is never testing what the user typed, but is instead
testing the new value.

can you tell me the rewrited version with my code

licensekey = input("Enter License Key")
licensekey = 824
if licensekey>=824:
    print("license key invalid rerun and try again")

We try not to write your code. We’re happy to explain things. Just
handing you working code does not help you to learn.

Have a look at my post, and then look at your code.

Also, put in some print statements.

For example, you might start by making your code be this:

 licensekey = input("Enter License Key")
 print( type(licensekey), repr(licensekey) )
 licensekey = 824
 print( type(licensekey), repr(licensekey) )
 if licensekey>=824:
     print("license key invalid rerun and try again")
     print("test was false")

See if the output informs your thinking about this problem.

still doesnt work

If you mean it behaves the same: yes. The print() calls do not change
anything. They show you the types and values of the licensekey
variable at various points. It is intended to make it possible for you
to figure out what changes might be needed to make the code behave as
you intend.

What was the output when you ran the new code?

<class ‘str’> ’ 824’
<class ‘int’> 824
license key invalid rerun and try again