Hello, I go by Pivot. Recently, I was trying to make a mini Pokemon damage calculator for a friend of mine that would have basic functions using loops and “if/elif/else” statements. The purpose was to make the process much faster and simpler by answering a couple of questions and using those answers to fill in blanks in the damage equation(s). I have tried multiple methods to fix the problem, but to no avail, so as a last resort, I decided to post here. I am only a few months new into using Python, and I currently have version 3.8. Below I will include the code. Any help would be greatly appreciated!

## Damage Calcs

## Stuff needed to import

import math

from fractions import Fraction## The basic questions

print(“Welcome to the shortcut damage calculator made by Pivot. Check below to begin.”)

print(“What is the base power?”)

power = input()

print(“What is the base attack stat? (It does not matter whether it is physical or special)”)

attack = input()

print(“What is the base defense stat? (It does not matter whether it is physical or special)”)

defense = input()## Bug-fixing.

power = int(power)

attack = int(attack)

defense = int(defense)## The calcs and stuff

## The default equation for damage calculation

dama = Fraction(Fraction(2 * 100/5) + 2 * power * attack/defense/50) + 2

dama * 1.0## The damage calculation plus any additional modifiers, A-F.

## A-F are replaced by further below code. However, not every letter is replaced, so each one is 1.

A = 1

B = 1

C = 1

D = 1

E = 1

F = 1

damaZ = dama * A * B * C * D * E * F

ABE = 2

ADC = 1## More questions

## If/else loop- if the user answers No, it will solve the equation and give the results.

## If user answers Yes, it will continue to next loop.

## Else statement is an error message meant to tell the user that their answer did not work, and will prompt them to retry.

f = input("Are there other factors? Enter 1 for Yes, 2 for No. ")

def factar():

if f == ADC:

print(“Okay, let me get your answer for you.”)

print(“Your damage is”, damaZ, “% out of the total.”)

quit`if f == ABE: print("Okay. Available commands are STAB, weather, burn, stat change, critical hit.") else: print("You must have input a wrong command. Sorry, but you'll have to restart the calculator. :(") print("If you believe this is a bug, please let me know!")`

## Questions regarding modifiers

## Each modifier substituted with a number for convenience

## Each if statement applies to each modifier, replacing A-F in the default equation and giving the solution, then stopping.

## Ideal process would be input true example -> if input == true example -> add modifier to default equation.

## Also ideal process would allow user to add multiple modifiers by going back to the first menu

## and reselecting a different number.

bite = B

print(“Which factor do you wish to add? 1:STAB, 2:Weather, 3:Burn, 4:Stat change.”)

bite = input()def biet():

for input in bite:

if bite == 1:

print(“Okay, let me get your answer for you.”)

A = 1.5

print(“Your damage is”, damaZ, “% out of the total.”)

if bite == 2:

print(“Okay, does this weather harm or help your user’s attack damage? 1:Harm, 2:Help.”)

weather = input()

if weather == 1:

B = 0.5

print(“Your damage is”, damaZ, “% out of the total.”)

if weather == 2:

B = 1.5

print(“Your damage is”, damaZ, “% out of the total.”)

if bite == 3:

C = 0.5

print(“Your damage is”, damaZ, “% out of the total.”)

if bite == 4:

print(“Please enter the numerical value of the stat change, from 6 to -6, including 0 as the default.”)

stat = 10

int(stat)

stat = input()`if stat == -6: D = 2/8 if stat == -5: D = 2/7 if stat == -4: D = 2/6 if stat == -3: D = 2/5 if stat == -2: D = 2/4 if stat == -1: D = 2/3 if stat == 0: D = 1 if stat == 1: D = 3/2 if stat == 2: D = 2 if stat == 3: D = 5/2 if stat == 4: D = 3 if stat == 5: D = 7/2 if stat == 6: D = 4`