Need trouble with my car wash program assignment

Python Help
1

my current code:

def car_wash_service(base_price, dictionary, service1, service2):
    total_price = base_price
    service_list = {service2, service1}
    print('ZyCar Wash')
    print(f'Base car wash -- ${base_price}')
    for service in service_list:
        if service in dictionary.keys():
            print(f'{service} -- ${dictionary[service]}')
            total_price += dictionary[service]
    print('----')
    print(f'Total price: ${total_price}')
    return total_price


if __name__ == "__main__":
    services = {'Air freshener': 1, 'Rain repellent': 2, 'Tire shine': 2, 'Wax': 3, 'Vacuum': 5}
    base_wash = 10
    total = 0
    service_choice1 = input()
    service_choice2 = input()
    car_wash_service(base_wash, services, service_choice1, service_choice2)

my error:
1:Compare outputkeyboard_arrow_up

0 / 2

Output differs. See highlights below. Special character legend

Input

Tire shine Wax

Your output starts with

ZyCar Wash Base car wash – $10 Wax – $3 Tire shine – $2 ---- Total price: $15

Expected output starts with

ZyCar Wash Base car wash – $10 Tire shine – $2 Wax – $3 ---- Total price: $15

2:Compare outputkeyboard_arrow_up

3 / 3

Input

Rain repellent -

Your output

ZyCar Wash Base car wash – $10 Rain repellent – $2 ---- Total price: $12

3:Compare outputkeyboard_arrow_up

3 / 3

Input

Vacuum Air freshener

Your output

ZyCar Wash Base car wash – $10 Vacuum – $5 Air freshener – $1 ---- Total price: $16

4:Compare outputkeyboard_arrow_up

2 / 2

Input

Your output correctly ends with

ZyCar Wash Base car wash – $10 ---- Total price: $10

5:Unit testkeyboard_arrow_up

2 / 2

car_wash_service() with the first example

Your output

ZyCar Wash Base car wash – $10 ---- Total price: $10

6:Unit testkeyboard_arrow_up

2 / 2

car_wash_service() with the second example

Your output

ZyCar Wash Base car wash – $13 Tire shine – $16 Air freshener – $20 ---- Total price: $49

2

Answer 1 looks correct to me; it’s just that the order is different, which shouldn’t matter.

1 Like
3

I do not understand your output of the test except this part which looks like an error in the testing code (not in your program) as Matthew noted:

I think you should explain the test output and tell what it has evaluated as being wrong.

4

even then, the grading system would not accept the order.
it needs to be in the exact order as implied.

5

You can reorder the entries of services as a workaround. That should work because in recent versions of Python dicts retain their insertion order.

6

Years later this post was super helpful for me.
For anyone else looking:
removing the β€œ.keys()”
from β€œif service in dictionary.keys():”
fixes the output order.

7

This is puzzling for me because service in dictionary.keys() returns the same result as service in dictionary.