New to Python and coding in general, can anyone help with my code?

[nikko]

I want the user to input their percentage and it will give them a grade, but when putting in anything other than a number it will give you an A* or a U. I assume this is because it puts numbers in the ‘alphabet’ along with letters above it and punctuation below it, so the >= signs are messed up. I’m not sure how to fix this, can anyone help.
Also, I am very knew to all of this, so any other tips/help would be appreciated!

[cameron (Cameron Simpson)]

By nikko via Discussions on Python.org at 27Apr2022 09:20:

Please post code inline as text, rather than as a screenshot.
Screenshots are not provided to users using email and offer challenges
to the visually impaired.

We can also copy/paste your code if it is text. Code should appear
between tripl backticks, eg:

```
your code here
```

Anyway, to your code…

I want the user to input their percentage and it will give them a grade, but when putting in anything other than a number it will give you an A* or a U. I assume this is because it puts numbers in the ‘alphabet’ along with letters above it and punctuation below it, so the >= signs are messed up.

You are correct in that assumption.

This is because you are working in strings.

Your code begins like this:

score = input("What was your percentage?")
if score >= "90":
    print("You got an A*")

The return from input() is a string (text). And your comparison is
also to a string: the expression "90" is a piece of text, not a
number.

To get correct behaviour you need score to be a number. For example,
this:

score = int(input("What was your percentage?"))

The takes the return string from input() and converts it to an integer
(the int type in Python). If the input is not a value integer the
int() call will raise an exception - this is not handled here, but you
can address that later.

Then you can perform a numeric test in your if-statement:

if score >= 90:

The expression 90 is an integer, as opposed to the expression "90"
which is a string.

This should get you on the way to working code.

If you need to work with fraction percentages such as 91.5, use
float instead of int.

Cheers,
Cameron Simpson cs@cskk.id.au

[vainaixr]

import operator as op
try:
  match (x := float(input('What was your percentage'))):
    case _ if op.and_(op.ge(x, 90), op.le(x, 100)): print(f'{x} => A+')
    case _ if op.and_(op.ge(x, 80), op.lt(x, 90)): print(f'{x} => A')
    case _ if op.and_(op.lt(x, 40), op.gt(x, 0)): print(f'{x} => U')
    case _ if op.or_(op.gt(x, 100), op.lt(x, 0)): print(f'invalid percentage')
except (ValueError): raise Exception('required integer or float')

[nikko]

Ah I see, you have to convert the numbers into integers instead of a string.
Thanks a lot, I will keep the screenshot thing in mind.

[rob42 (Rob)]

You’ve maybe got your answer by now, but building on the code that you posted, this is an example of how that could be adapted:

score = input("What was your percentage? ")

try:
    your_score = float(score)

    if your_score >= 90:
        your_grade = "A*"

    elif your_score >= 80:
        your_grade = "A"

    elif your_score >= 70:
        your_grade = "B"

    elif your_score >= 60:
        your_grade = "C"

    elif your_score >= 50:
        your_grade = "D"

    elif your_score >= 40:
        your_grade = "E"

    else: your_grade = "U"

except ValueError:
    print("Please enter your score as a number. e.g: if you got 87.4% enter 87.4 at the prompt.")
    your_grade = ""

if your_grade != "":
    print("Your grade is: "+your_grade)