Popping the Call stack

Python Help
1

Are there any commands, methods, functions… to allow the manipulation of the CALL STACK in python. For example if a recursive function was looking for a specific value during its execution and found the value and needs to return the value but there are pending returns in the call stack is there a way to remove (not using return) such as pop, to remove them off the CALL STACK at the programmers discretion?

2

What do you have against return?

3

You see my return to my main is on the bottom of the call stack, but piled on top are still unresoved recussive returns which I want to eliminate NOT by returning, but by removing.

Returning only continues the process but I have already found what I am looking for.

4

I don’t know about your desired way, but you could maybe use raise, and catch it in your main.

5

I am not familiar with raise or catch maybe that is what I am looking for I will check on this. But yes, another way to solve my issue as your reply is hinting is to raise an exeption and get out. BUT i need to get out with my answer, return to the main, AND make sure I have not left a stack full of data.

If the raise or the catch clear off or delete the values left on the stack that would be great, but I don’t know how I could get back to the main with my answer if the stack is gone.

That said, I will investigate the raise and catch - thanks

6

Small demo, quickly finds and prints the index where gold is found:

def find(xs, x, i):
    if xs[i] == x:
        raise StopIteration(i)
    find(xs, x, i + 1)
    find(xs, x, i - 1)

def main():
    xs = ['sand'] * 100 + ['gold']
    try:
        find(xs, 'gold', 0)
    except StopIteration as e:
        print(e.value)

main()

Attempt This Online!

7

This might work. I see where you are going with this. I will give it a try! Get back to you soon. Thanks!

8

IT WORKED!!! Thank You !!!