I would suggest to put your efford in algorithm. Define it in natural language and then translate it into Python.
It boils down to how to determine result. Basically there can be two outcomes: (1) draw or (2) either side wins.
Draw is simple - if choices are equal. If it’s not a draw then to determine winner there are actually only three combinations (first choice wins): Rock-Scissors, Paper-Rock, Scissors-Paper. If it’s not draw and not first choice wins then second choice is winner.
Based on that it is possible to write much simpler code:
first_wins = [('Rock', 'Scissors'), ('Paper', 'Rock'), ('Scissors', 'Paper')]
if first_choice == second_choice:
elif (first_choice, second_choice) in first_wins:
# first_choice wins
# second_choice wins
There are other ways to determine a result but I think this is good for starters.