of this:
text = ’ , 1, 8, 17, 30, 31, 34, 35 2, 5, 12, 22, 25, 27, 33, 9, 10, 11, 14, 15, 21, 29, ’
I would like these:
text1 = ‘1, 8, 17, 30, 31, 34, 35’
text2 = ‘2, 5, 12, 22, 25, 27, 33’
text3 = ‘9, 10, 11, 14, 15, 21, 29’
How can it be solved? Thanks!
You have already done it…
Thanks! I wish a Python code would do it! Is there a solution?
Of course. Many. Depends on the details of what you want, which you’re not telling us.
My secret wish is to find a simple solution as I’m trying to slice and dice and it’s difficult. That’s it.
text1 = text[2:27]
text2 = text[29:53]
text3 = text[55:79]
Well, now you’ve already done the slicing and dicing as well.
Do you have more details to share? The “smaller strings”, do they require 7 comma separated values? It can be difficult to provide guidance without the full picture 
A good place to start is having a look at str methods. One of the best ways to “slice and dice” a string (without slicing) is str.split. Note also, that a strings have concatenation method called join.
Python also has a regular expressions facility.
1 Like
I am happy to share the full code. But the point is that this list is constantly changing when the code is running. Therefore, there is always a difference in the slices, because it is not known where the one- and two-digit numbers are. However, this would be important for PDF saving!
def szelvenyek_pdfbe(self):
"""elmenti a lottószámokat PDF -be!"""
text_szoveg = self.lotto_text.get("1.0", tk.END)
# text_szoveg = '\n9, 10, 15, 25, 27, 29, 31\n2, 8, 14, 21, 22, 30, 35\n1, 5, 6, 11, 17, 19, 33\n12, 34\n'
text_szoveg = text_szoveg.replace("\n", ", ")
# text_szoveg = ' 1, 8, 17, 30, 31, 34, 35 2, 5, 12, 22, 25, 27, 33 9, 10, 11, 14, 15, 21, 29 6, 19 '
text1 = text_szoveg[2:27]
text2 = text_szoveg[29:53]
text3 = text_szoveg[55:79]
text4 = text_szoveg[80:]
pdfbeMent.PdfMentes(text1,
text2,
text3,
text4,
self.fajlnev_entry.get())
self.szelveny_ment_label.configure(text='MENTVE!')
I posted a code snippet. I formulated the point above that the text string is constantly changing. Therefore, the slicing may be inaccurate.
Strip the leading and trailing commas and spaces with .strip and then split it on commas with .split.
You now have a list of strings.
Slice the list into groups of 7 and join each group with .join and a comma.
1 Like
How do you know they want that? Maybe they want 3 groups. Seems more likely, even, as they want them in separate variables, and it would be bad to have a dynamic number of variables.
… Unless both things are equal because they always have exactly 21 numbers. So many details they’re keeping secret…
To solve the problem, we need to be able to understand: what is the rule that tells you, where the string should be sliced?
Thanks! No secret. There is a Hungarian lottery statistics website: Lottó 567 - Lottó statisztikák
From here I buy 4 lists of 7 numbers each. I edit these lists into a connected list. I get a list of 4x7=28 numbers. This is what I process with my program: Save to a json file, then scan and display in tkinter Text.
Extraction from Text, I mix the 28 numbers. I reduce the number repetitions to one piece, so usually 23 pieces remain. I will divide this into the numbers of the Scandinavian lottery tickets, which can be made into seven pieces, three tickets in total.
Some numbers are missing. I display these three series of numbers again in tkinter Text, then read them from here and save them to PDF.
So a problem arises when slicing.
I found the solution at night: instead of 1, 2, 3, 4, etc., 01, 02, 03, etc. I have to apply. After a little investigation, I found the solution with the help of print(help(str.zfill)) and data = (f"{1:02}").
You are a great team!
