Log to read and display as per even and odd

Python Help
1

Hi Team
I have a question to split the srr.txt read data it has 1,2,3,4,5,6,7,8,9,10 with is divided by 0 then display first then there next output. i,e 2,4,6,8 oput and 1,3,7,9 is next output. how can I achieve with strip using lambda?

s=open(‘srr.txt’,‘r’)
so=sorted(s.readlines(),key=lambda item: int(item.strip().split(’\t’)[-1]))

print(so)

2

Why does it have to be with lambda? Can’t you define a function to do
it?

Even if you need a one-liner, start by writing a many-line function to
solve the problem, and then compress it down to one-line.

Personally, I would do something like this:

with open('srr.txt') as f:
    evens = []
    odds = []
    for line in f:
        line = line.strip()
        if not line:
            continue
        num = int(line)
        if num % 2 == 1:
            odds.append(num)
        else:
            evens.append(num)
odds.sort()
evens.sort()
evens.extend(odds)
print(evens)  # technically evens followed by odds
3

Your question is unclear and hard to decipher, but if you just want to separate odds and evens, there is a partition recipe that is already implemented in a library. You can pip install more-itertools or choose to implement the recipe yourself.